Hi! The question is to find the derivative of: 0.5 sin2x + cosx for 0 < x < 2pi My answer is: sinx + 0.5 cos 2x, but I am not sure if it's correct. Thanks in advance, Amine
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Originally Posted by Aminekhadir Hi! The question is to find the derivative of: 0.5 sin2x + cosx for 0 < x < 2pi My answer is: sinx + 0.5 cos 2x, but I am not sure if it's correct. Thanks in advance, Amine $\displaystyle \frac{d}{dx} \sin(ax) = a\, \cos(ax)$ The derivative of cos is -sin and you forgot the chain rule on the sin(2x) term $\displaystyle \frac{d}{dx}[0.5\sin(2x)+ \cos(x)] = \cos(2x)-\sin(x)$
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