Rearrange the second equation into y=mx+c to find the gradient

therefore the gradient is 12

If the tangent [ie: f'(x)] is parallel to this line it must be equal.

Find f'(x) and set it equal to 12 then get x.

Spoiler:

Put your value(s) of x into f(x) to get a co-ordinate.

Spoiler:

You can now use the equation of a straight line

To my knowledge I am not sure if you can get an explicit solution