Find an equation of the line that is tangent to the graph of f(x)=x^3 and parallel to the line: 12x-y+5=0

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- February 5th 2010, 03:46 PMphalangetangent line equations
Find an equation of the line that is tangent to the graph of f(x)=x^3 and parallel to the line: 12x-y+5=0

- February 5th 2010, 03:55 PMe^(i*pi)
Rearrange the second equation into y=mx+c to find the gradient

therefore the gradient is 12

If the tangent [ie: f'(x)] is parallel to this line it must be equal.

Find f'(x) and set it equal to 12 then get x.

__Spoiler__:

Put your value(s) of x into f(x) to get a co-ordinate.

__Spoiler__:

You can now use the equation of a straight line

To my knowledge I am not sure if you can get an explicit solution