f(x)= ((x+2)/2), if x<4
f(x)= ((13-x)/3) if x>4
Is this function continuous at x=4? If not, is it removable discontinuity or non-removable discontinuity?
one has a positive slope, the other negative.
f(4) = 3 in both cases, if 4 was allowed in the domain.
The "hole" at x=4 can be removed by filling it in,
therefore it is a removeable discontinuity.
The graph would then be continuous, albeit non-differentiable at x=4.