Find the integral of: [g'(x)] / [g(x)]^2 I got as an anser: [g(x)] / 1/3[g(x)]^3 ...but I'm not sure if I broke some kind of rules.
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Originally Posted by WartonMorton Find the integral of: [g'(x)] / [g(x)]^2 I got as an anser: [g(x)] / 1/3[g(x)]^3 ...but I'm not sure if I broke some kind of rules. hi warton,.. i suggest you to use the substitution method
Originally Posted by WartonMorton Find the integral of: [g'(x)] / [g(x)]^2 I got as an anser: [g(x)] / 1/3[g(x)]^3 ...but I'm not sure if I broke some kind of rules. therefore
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