Find the Integral of (t^2 - a)(t^2 - b) * dt. I tried combining to (t^4 -bt^2 - at^2 + ab) but this didn't give me much.
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Originally Posted by WartonMorton Find the Integral of (t^2 - a)(t^2 - b) * dt. I tried combining to (t^4 -bt^2 - at^2 + ab) but this didn't give me much. No, It gives. $\displaystyle \int (t^4 -bt^2 - at^2 + ab) dt = \int t^4 dt - (a+b)\int t^2 dt + ab \int dt$.
Originally Posted by WartonMorton Find the Integral of (t^2 - a)(t^2 - b) * dt. I tried combining to (t^4 -bt^2 - at^2 + ab) but this didn't give me much. hi warton,. now you only need to integrate it using the integral formula for polynomial, $\displaystyle \int t^n ~dt = \frac{1}{n+1} t^{n+1}$, as long as $\displaystyle n \not = -1$
Originally Posted by dedust hi warton,. now you only need to integrate it using the integral formula for polynomial, $\displaystyle \int t^n ~dt = \frac{1}{n+1} t^{n+1}$, as long as $\displaystyle n \not = -1$ Actually, Its name is "Power Rule".
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