# Indefinite Integral

• February 5th 2010, 06:36 AM
WartonMorton
Indefinite Integral
Find the Integral of (t^2 - a)(t^2 - b) * dt.

I tried combining to (t^4 -bt^2 - at^2 + ab) but this didn't give me much.
• February 5th 2010, 06:58 AM
General
Quote:

Originally Posted by WartonMorton
Find the Integral of (t^2 - a)(t^2 - b) * dt.

I tried combining to (t^4 -bt^2 - at^2 + ab) but this didn't give me much.

No, It gives.
$\int (t^4 -bt^2 - at^2 + ab) dt = \int t^4 dt - (a+b)\int t^2 dt + ab \int dt$.
• February 5th 2010, 07:02 AM
dedust
Quote:

Originally Posted by WartonMorton
Find the Integral of (t^2 - a)(t^2 - b) * dt.

I tried combining to (t^4 -bt^2 - at^2 + ab) but this didn't give me much.

hi warton,.
now you only need to integrate it using the integral formula for polynomial,

$\int t^n ~dt = \frac{1}{n+1} t^{n+1}$, as long as $n \not = -1$
• February 5th 2010, 07:05 AM
General
Quote:

Originally Posted by dedust
hi warton,.
now you only need to integrate it using the integral formula for polynomial,

$\int t^n ~dt = \frac{1}{n+1} t^{n+1}$, as long as $n \not = -1$

Actually, Its name is "Power Rule".