Results 1 to 4 of 4

Math Help - Prove (x^1/2)>ln x for x>1

  1. #1
    Newbie
    Joined
    Feb 2010
    Posts
    6

    Prove (x^1/2)>ln x for x>1

    How can prove this
    (x^1/2)>ln x for x>1
    Last edited by mr fantastic; February 5th 2010 at 12:35 PM. Reason: Changed post title
    Follow Math Help Forum on Facebook and Google+

  2. #2
    No one in Particular VonNemo19's Avatar
    Joined
    Apr 2009
    From
    Detroit, MI
    Posts
    1,823
    Quote Originally Posted by ha11 View Post
    How can prove this
    (x^1/2)>ln x for x>1
    x^{1/2}>\ln{x}\Rightarrow{e}^{x^{1/2}}>x. which is clearly true for all x>1
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Math Engineering Student
    Krizalid's Avatar
    Joined
    Mar 2007
    From
    Santiago, Chile
    Posts
    3,654
    Thanks
    12
    You'll need to replace that \implies by an \iff in order your proof work.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Newbie
    Joined
    Feb 2010
    Posts
    6
    thanks, but I want the prove
    Last edited by ha11; February 5th 2010 at 10:44 AM.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Prove
    Posted in the Calculus Forum
    Replies: 4
    Last Post: October 10th 2010, 11:28 AM
  2. Prove(10)
    Posted in the Trigonometry Forum
    Replies: 5
    Last Post: February 26th 2010, 04:16 AM
  3. Replies: 2
    Last Post: August 28th 2009, 02:59 AM
  4. How do I prove b^x * b^y = b ^ x + y on R?
    Posted in the Calculus Forum
    Replies: 2
    Last Post: October 25th 2008, 12:15 AM
  5. Prove:
    Posted in the Algebra Forum
    Replies: 1
    Last Post: October 24th 2008, 11:45 PM

Search Tags


/mathhelpforum @mathhelpforum