a mass attacked to a spring has a position function given by s(t)=2sin(4t)
t=sec s= in
velocity at t=4 is -7.6in/sec got that from s'(t)=8cos(16)
acceleration at t=4 is ?
how do i go about finding acceleration?
Accelleration is the second derivative of the position function, or the first derivative of the velocity function.
You already found s'(t) = v(t) = 8cos(4t) + c
To find c, plug in t=4 and v(t) = -7.6.
Then, take the derivative of the velocity equation. That will give you your acceleration function. Then plug in t = 4 into the acceleration function.
Edit: Sorry about the double post... I was too slow I guess.