I get the same answer as you and so does wolframalpha: integral of 2dx/(xln(5x)) - Wolfram|Alpha
Is the correct answer given?
i'm scratching my head with this one:
evaluate the indefinite integral:
the integral of 2dx/(xln(5x))
so what i do is pull the 2 in front of the integral
use u-substitution
u=ln5x
du = 1/5x *5 dx = 1/x dx
so i get
2* integral of 1/u du
which gives me
2*lnu + C
and substituting back in gives me
2*ln(ln(5x))+C
but apparently thats not right . can anyone tell me where i'm going wrong?
I get the same answer as you and so does wolframalpha: integral of 2dx/(xln(5x)) - Wolfram|Alpha
Is the correct answer given?