Use ln(a/b) = lna - lnb
and ln(a^b) = bln(a)
y = (x-4)^-3(sin(x))^4 / (x^2-2x)^2(e^x^3)
lny = [-3sin(x)] ln(x-4) -[ e^x^3] ln (x^2 -2x)
Now differentiate:
y '/y = etc....
y = (x-4)^-3(sin(x))^4 / (x^2-2x)^2(e^x^3)
y'= y*____________
I set it up as:
sin^4(x) / (x-4)^3(x^2-2x)^2(e^x^3)
Take the ln of both sides:
ln y= 4sin^3(x)cos(x) / ((3(x-4)^2)(2(x^2-2x))(2x-1)(3x))
But that's wrong. What do I do with this?