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Math Help - Isosceles right triangle problem

  1. #1
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    Isosceles right triangle problem

    Isosceles right triangle problem (solids with know cross-sections)

    I have a isosceles right triangle with a known base (square root of (4-x^2) how can I find the height? Do I need to use a law of sin/cos or is there an easier way?
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  2. #2
    MHF Contributor Calculus26's Avatar
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    The height is the length of one of the equal sides the area is 1/2s^2

    since it is a rt triangle s^2 +s^2 = h^2

    s= h/sqrt(2)

    in your eg h = 4-x^2
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  3. #3
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    Hello, icu812!

    Did you make a sketch?


    I have a isosceles right triangle with a known base:\ . b \,=\,\sqrt{4-x^2}

    How can I find the height?
    Code:
                      *
                    * | *
                  *   |   *
                *     |b/2  *
              *       |       *
            * 45     |     45 *
          *  *  *  *  *  *  *  *  *
          : - b/2 - - : - - b/2 - :
          : - - - - - b - - - - - :


    Got it?

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  4. #4
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    Thumbs up

    Yes thanks a lot. It has been probaly 15 years since I had geometry. We just did solids of revolution, and started solids with known cross-section today.
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