The height is the length of one of the equal sides the area is 1/2s^2
since it is a rt triangle s^2 +s^2 = h^2
s= h/sqrt(2)
in your eg h = 4-x^2
Isosceles right triangle problem (solids with know cross-sections)
I have a isosceles right triangle with a known base (square root of (4-x^2) how can I find the height? Do I need to use a law of sin/cos or is there an easier way?