Isosceles right triangle problem (solids with know cross-sections)
I have a isosceles right triangle with a known base (square root of (4-x^2) how can I find the height? Do I need to use a law of sin/cos or is there an easier way?
Isosceles right triangle problem (solids with know cross-sections)
I have a isosceles right triangle with a known base (square root of (4-x^2) how can I find the height? Do I need to use a law of sin/cos or is there an easier way?
Hello, icu812!
Did you make a sketch?
I have a isosceles right triangle with a known base:\ .$\displaystyle b \,=\,\sqrt{4-x^2}$
How can I find the height?Code:* * | * * | * * |b/2 * * | * * 45° | 45° * * * * * * * * * * : - b/2 - - : - - b/2 - : : - - - - - b - - - - - :
Got it?