# Math Help - Isosceles right triangle problem

1. ## Isosceles right triangle problem

Isosceles right triangle problem (solids with know cross-sections)

I have a isosceles right triangle with a known base (square root of (4-x^2) how can I find the height? Do I need to use a law of sin/cos or is there an easier way?

2. The height is the length of one of the equal sides the area is 1/2s^2

since it is a rt triangle s^2 +s^2 = h^2

s= h/sqrt(2)

in your eg h = 4-x^2

3. Hello, icu812!

Did you make a sketch?

I have a isosceles right triangle with a known base:\ . $b \,=\,\sqrt{4-x^2}$

How can I find the height?
Code:
                  *
* | *
*   |   *
*     |b/2  *
*       |       *
* 45°     |     45° *
*  *  *  *  *  *  *  *  *
: - b/2 - - : - - b/2 - :
: - - - - - b - - - - - :

Got it?

4. Yes thanks a lot. It has been probaly 15 years since I had geometry. We just did solids of revolution, and started solids with known cross-section today.