Thread: find arc length

compute thearc length of the curve
f(x)= ln(1+x^2) -1/16 x^2 -1/8 ln(x)

<a> ln 9 +3/16 +7/8 ln2
<b> ln 5 +3/16 -7/8 ln2
<c> ln 9 +3/16
<d> ln5- 3/16

Originally Posted by harry

compute thearc length of the curve
f(x)= ln(1+x^2) -1/16 x^2 -1/8 ln(x)

<a> ln 9 +3/16 +7/8 ln2
<b> ln 5 +3/16 -7/8 ln2
<c> ln 9 +3/16
<d> ln5- 3/16

Aren't there some limits involved here?

RonL

compute thearc length of the curve
f(x)= ln(1+x^2) -1/16 x^2 -1/8 ln(x)
limits of x are [1,2]

<a> ln 9 +3/16 +7/8 ln2
<b> ln 5 +3/16 -7/8 ln2
<c> ln 9 +3/16
<d> ln5- 3/16