OK here is the question.
Find an equation of the plane that contains the lines given by
(x-1)/-2 = y = z+1
(x+1)/-2 = y-1 = z-2
This is what I did.
I found 2 points for the first line and 2 points for 2nd line
A= (0 , 0.5, -0.5)
B=(1 , 0 , 1)
C= (0, 0.5, 1.5)
D= (1, 0, 1)
then i got their vector equations
AB = <1, -0.5, 1.5>
CD = <1, -0.5, -0.5>
What now? Do i get their cross product? I did cross product, substituted it with a point on the plane, point A i think, and then got the equation x+2y = 1.
But the answer doesnt seem right to me, so I would like some clarification as to whether I did anything wrong.