Hello all. Firstly, I would like to sorry that I post my thread i think not in the exact segment, because I don't know really where to post it. I was wondering if someone could help me, because I am in a real trouble.

I have to solve this equation and I don't know how to do this. Just the last exercise for my full work.

i would be very grateful if you people could help me.

This is that equation:

2x^2 - 3x - 1 - 3/x + 2/x^2 = 0

2. $2x^2 - 3x - 1 - \frac{3}{x} + \frac{2}{x^2} = 0$

You multiply each side through by $x^2$ giving

$2x^4 - 3x^3 - x^2 - 3x + 2 = 0$

Now solve using the factor theorm.

Hint: $f(2)=0$

3. Originally Posted by pickslides
$2x^2 - 3x - 1 - \frac{3}{x} + \frac{2}{x^2} = 0$

You multiply each side through by $x^2$ giving

$2x^4 - 3x^3 - x^2 - 3x + 2 = 0$

Now solve using the factor theorm.

Hint: $f(2)=0$
Omg, thank you a lot, however I am 12 former and I don't know this factor theorem. I will say my teacher that it is impossible to do it.

4. Originally Posted by fielmann
Omg, thank you a lot, however I am 12 former and I don't know this factor theorem. I will say my teacher that it is impossible to do it.
It is not impossible to do. If your in form 12 you are expected to know the factor theorem, well in my country anyhow!