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Math Help - Slope Tangent line

  1. #1
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    Slope Tangent line

    Hey guy wondering if someone could help me out here.

    I need to find a formula for the slope of the tangent line to the graph of f at a general point x=xknot

    and then use the formula obtained in first part to find the slope of the tangent line for the given value of xknot... heres the function f(x)=  \frac{1}{\sqrt{x}} ; xknot=4

    I'm having trouble with the initial setup...
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  2. #2
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    Quote Originally Posted by nate19 View Post
    Hey guy wondering if someone could help me out here.

    I need to find a formula for the slope of the tangent line to the graph of f at a general point x=xknot

    and then use the formula obtained in first part to find the slope of the tangent line for the given value of xknot... heres the function f(x)=  \frac{1}{\sqrt{x}} ; xknot=4

    I'm having trouble with the initial setup...

    In general, de slope of the tangent line to the graph of a function f at a general point (x_0,y_0) is f'(x_0) ,provided the function is derivable at that point.

    Tonio
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  3. #3
    Member integral's Avatar
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    \frac{d}{dx} \sqrt{x}^{-1}, x \neg 4= -\frac{1}{2x^{ \frac{3}{2}}}
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  4. #4
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    well thanks for the help guys but i'm not allowed to use derivatives or shortcuts yet.. the only formulas I can use are ..
    lim x-->x0 f(x) - f(x0)/ x-x0
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  5. #5
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    its just the same. the formula that u are given to use will actually give the derivative and thus the slope.
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  6. #6
    MHF Contributor Calculus26's Avatar
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    See attachment
    Attached Thumbnails Attached Thumbnails Slope Tangent line-limit.jpg  
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  7. #7
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    finding derivatives ab-initio is cubersome
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