I'm not exactly sure how to implement the formula for this.

$\displaystyle \int{x^2 + 1} dx$ from 0 to 4

And the question wants MID(2), which I assume means to divide it into two subsections.

How would I find this?

So far I have drawn the graph and gotten delta x to be 1. So I have

$\displaystyle f(2 + \frac{2}{2})(1) + f(10 + \frac{2}{2})(1)$

$\displaystyle = f(5/2) + f(21/2)$

$\displaystyle = (\frac{5}{2})^2 + 1) + ((\frac{21}{2})^2 + 1)$

according to the equation given to me in my notes, which was:

$\displaystyle \int{f(x)} = f(x_1 + \frac{delta x_1} {2}) (delta x_1) + f (x_2 + \frac{delta x_2} {2})(delta x_2)$

So I got 118.5. Is that right?