I suppose this is really simple, but how does one go from: $\displaystyle (x-1)^2 + y^2 = 1$ to the equivalent polar coordinate equation. Thanks.
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Plug'n Chug! It's not magic. It's an algebra problem. $\displaystyle x = r\cdot\cos(\theta)$ $\displaystyle y = r\cdot\sin(\theta)$ Expand, Simplify, etc.
Originally Posted by nunos I suppose this is really simple, but how does one go from: $\displaystyle (x-1)^2 + y^2 = 1$ to the equivalent polar coordinate equation. Thanks. $\displaystyle x=r\cos \theta\,,\,y=r\sin \theta$ , and then $\displaystyle (x-1)^2+y^2=1\Longrightarrow x^2-2x+y^2=0\Longrightarrow r(r-2\cos \theta) = 0$ $\displaystyle \Longrightarrow r = 2\cos \theta$ Tonio
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