$\displaystyle \lim [\frac{10^n+1}{2*10^n-1}]$ here is my work: $\displaystyle \lim \frac{10^n(1+1)}{10^n(2*1-1)}$ = $\displaystyle \frac{2}{1} $ But that was wrong..correct answer was $\displaystyle \frac{1}{2}$
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There is a mistake when you factorized : $\displaystyle 10^n+1 = 10^n\left(1+\frac 1{10^n}\right)$
Originally Posted by Henryt999 $\displaystyle \lim [\frac{10^n+1}{2*10^n-1}]$ Assuming $\displaystyle \color{blue}n\to\infty$: Devide top and bottom by $\displaystyle \color{blue}10^n$.
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