Can someone please help me with this problem I am stuck! My first step has been: dv = 3 dx v= 3x u = arctan(2x) du = [1/(1+4x^2)]*2 Giving me... Thanks!!!!!
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Originally Posted by stickyMATH Can someone please help me with this problem I am stuck! My first step has been: dv = 3 dx v= 3x u = arctan(2x) du = [1/(1+4x^2)]*2 Giving me... Thanks!!!!! To solve the new integral substitute .
Ahhhh I was not going that direction! Thanks!
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