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Math Help - [SOLVED] Integration by parts help...

  1. #1
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    Talking [SOLVED] Integration by parts help...

    Can someone please help me with this problem I am stuck!

    <br />
\int 3arctan(2x)dx<br />

    My first step has been:
    dv = 3 dx
    v= 3x
    u = arctan(2x)
    du = [1/(1+4x^2)]*2

    Giving me...
    <br />
3xarctan(2x) - \int 3x*[1/(1+4x^2)]*2dx

    Thanks!!!!!
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  2. #2
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    Quote Originally Posted by stickyMATH View Post
    Can someone please help me with this problem I am stuck!

    <br />
\int 3arctan(2x)dx<br />

    My first step has been:
    dv = 3 dx
    v= 3x
    u = arctan(2x)
    du = [1/(1+4x^2)]*2

    Giving me...
    <br />
3xarctan(2x) - \int 3x*[1/(1+4x^2)]*2dx

    Thanks!!!!!
    To solve the new integral substitute w = 1 + 4x^2.
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  3. #3
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    Jan 2010
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    Ahhhh I was not going that direction! Thanks!
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