# Math Help - [SOLVED] Integration by parts help...

1. ## [SOLVED] Integration by parts help...

Can someone please help me with this problem I am stuck!

$
\int 3arctan(2x)dx
$

My first step has been:
dv = 3 dx
v= 3x
u = arctan(2x)
du = [1/(1+4x^2)]*2

Giving me...
$
3xarctan(2x) - \int 3x*[1/(1+4x^2)]*2dx$

Thanks!!!!!

2. Originally Posted by stickyMATH
Can someone please help me with this problem I am stuck!

$
\int 3arctan(2x)dx
$

My first step has been:
dv = 3 dx
v= 3x
u = arctan(2x)
du = [1/(1+4x^2)]*2

Giving me...
$
3xarctan(2x) - \int 3x*[1/(1+4x^2)]*2dx$

Thanks!!!!!
To solve the new integral substitute $w = 1 + 4x^2$.

3. Ahhhh I was not going that direction! Thanks!