[SOLVED] Integration by parts help...

Printable View

February 1st 2010, 12:01 AM
stickyMATH

[SOLVED] Integration by parts help...

Can someone please help me with this problem I am stuck! (Headbang)

$ \int 3arctan(2x)dx $

My first step has been:
dv = 3 dx
v= 3x
u = arctan(2x)
du = [1/(1+4x^2)]*2

Giving me...
$ 3xarctan(2x) - \int 3x*[1/(1+4x^2)]*2dx$

Thanks!!!!! (Rock)
February 1st 2010, 12:03 AM
mr fantastic

Quote:

Originally Posted by stickyMATH

Can someone please help me with this problem I am stuck! (Headbang)

$ \int 3arctan(2x)dx $

My first step has been:
dv = 3 dx
v= 3x
u = arctan(2x)
du = [1/(1+4x^2)]*2

Giving me...
$ 3xarctan(2x) - \int 3x*[1/(1+4x^2)]*2dx$

Thanks!!!!! (Rock)

To solve the new integral substitute $w = 1 + 4x^2$ .
February 1st 2010, 12:12 AM
stickyMATH

Ahhhh I was not going that direction! Thanks!

All times are GMT -8. The time now is 07:46 AM.