[SOLVED] Integration by parts help...

Can someone please help me with this problem I am stuck! (Headbang)

$\displaystyle
\int 3arctan(2x)dx
$

My first step has been:
dv = 3 dx
v= 3x
u = arctan(2x)
du = [1/(1+4x^2)]*2

Giving me...
$\displaystyle
3xarctan(2x) - \int 3x*[1/(1+4x^2)]*2dx$

Thanks!!!!! (Rock)

Quote:

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Originally Posted by stickyMATH

Can someone please help me with this problem I am stuck! (Headbang)

$\displaystyle
\int 3arctan(2x)dx
$

My first step has been:
dv = 3 dx
v= 3x
u = arctan(2x)
du = [1/(1+4x^2)]*2

Giving me...
$\displaystyle
3xarctan(2x) - \int 3x*[1/(1+4x^2)]*2dx$

Thanks!!!!! (Rock)

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To solve the new integral substitute $\displaystyle w = 1 + 4x^2$.

Ahhhh I was not going that direction! Thanks!