# Math Help - My mind is escaping me

1. ## My mind is escaping me

I seem to be having a huge case of mind lock, i can't seem to remember how to solve for the original function to evaluate the integral:
$
\int_0^1 \frac{1}{2^x}dx$

2. Note that 1/(2^x)=2^-x.

Also recall that d/dx(2^x)=log(2)*2^x

So our integral is -1/log(2) * 2^(-x)+C. We now this because when we take the derivative, we have a -log(2) to get rid of so that we will be left with 2^(-x) (evaluate between 0 and 1 of course).

3. Originally Posted by penguinpwn
I seem to be having a huge case of mind lock, i can't seem to remember how to solve for the original function to evaluate the integral:
$
\int_0^1 \frac{1}{2^x}dx$
$\frac{1}{2^x}=(\frac{1}{2})^x$.

4. BTW: It is impossible for "My mind is escaping me".
One's mind is simply one's brain.

5. Originally Posted by Plato
BTW: It is impossible for "My mind is escaping me".
One's mind is simply one's brain.
Wouldn't that be like saying that my heartbeat is my heart?

6. Originally Posted by Plato
BTW: It is impossible for "My mind is escaping me".
One's mind is simply one's brain.
That is not true. "mind" and "brain" are NOT synonymous.

7. This thread can be continued in the Philosophy subforum (if so desired).