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Math Help - My mind is escaping me

  1. #1
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    My mind is escaping me

    I seem to be having a huge case of mind lock, i can't seem to remember how to solve for the original function to evaluate the integral:
    <br />
\int_0^1 \frac{1}{2^x}dx
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  2. #2
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    Note that 1/(2^x)=2^-x.

    Also recall that d/dx(2^x)=log(2)*2^x

    So our integral is -1/log(2) * 2^(-x)+C. We now this because when we take the derivative, we have a -log(2) to get rid of so that we will be left with 2^(-x) (evaluate between 0 and 1 of course).
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  3. #3
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    Quote Originally Posted by penguinpwn View Post
    I seem to be having a huge case of mind lock, i can't seem to remember how to solve for the original function to evaluate the integral:
    <br />
\int_0^1 \frac{1}{2^x}dx
    \frac{1}{2^x}=(\frac{1}{2})^x.
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  4. #4
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    BTW: It is impossible for "My mind is escaping me".
    One's mind is simply one's brain.
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  5. #5
    MHF Contributor Bruno J.'s Avatar
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    Quote Originally Posted by Plato View Post
    BTW: It is impossible for "My mind is escaping me".
    One's mind is simply one's brain.
    Wouldn't that be like saying that my heartbeat is my heart?
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  6. #6
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    Quote Originally Posted by Plato View Post
    BTW: It is impossible for "My mind is escaping me".
    One's mind is simply one's brain.
    That is not true. "mind" and "brain" are NOT synonymous.
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  7. #7
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    This thread can be continued in the Philosophy subforum (if so desired).

    Thread closed.
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