Volumes by Cross-Sections

A solid has at its base the region bounded by the parabola x-y^2 = -8 and the left branch of the hyperbola x^2-y^2-4=0. The vertical slices perpendicular to the x-axis are squares. Find the volume of the solid. This is the full problem.

I was able to find out the points of intersection, which were x=-3 and x=4. I am not sure what the cross-sectional area is.

Quote:

---

Originally Posted by dalbir4444

A solid has at its base the region bounded by the parabola x-y^2 = -8and the left branch of the hyperbola x^2-y^2-4=0. The vertical slices perpendicular to the x-axis are squares. Find the volume of the solid.

---

Could you please post the problem as it is written and show your attempt at the solution?

hi dalbir4444,

the left side of the hyperbola is

You've identified the x co-ordinate of the points of intersection.
x=4 is unnecessary, as the parabola intersects the rightside part there.

To calculate the area of the bounded region, you only need the area of the part above the x-axis and multiply by 2.

If you also calculate where the parabola and hyperbola cut the x-axis to the left of the y-axis, then you can integrate under the parabola from x=-8 to -3
and integrate under the hyperbola from x=-3 to x=-2.

That will be one way to calculate the area between the curves.

I can't visualise the object itself however, as your question mentions a square.