1. Trig Integral Help

I have an up-coming calc test and one of the review problems that has me stumped is:

Show that:
$\int_0^1 {\sqrt{2-x^2}}$ = $\pi/4 +1/2$

Thanks ahead of time for the help

$\int_0^1 {\sqrt{2-x^2}}$ = $\pi/4 +1/2$
Substitute $x = \sqrt{2} \sin \theta$.
3. Thank you very much. I somehow had kept missing that $\sqrt2$