I have an up-coming calc test and one of the review problems that has me stumped is: Show that: $\displaystyle \int_0^1 {\sqrt{2-x^2}}$ = $\displaystyle \pi/4 +1/2$ Thanks ahead of time for the help
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Originally Posted by Spudwad I have an up-coming calc test and one of the review problems that has me stumped is: Show that: $\displaystyle \int_0^1 {\sqrt{2-x^2}}$ = $\displaystyle \pi/4 +1/2$ Thanks ahead of time for the help Substitute $\displaystyle x = \sqrt{2} \sin \theta$.
Thank you very much. I somehow had kept missing that $\displaystyle \sqrt2$
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