Originally Posted by
abstraktz Hi, I just need clarification on the constant rule of derivatives.
The derivative of a constant = 0. So if after applying the quotient or product rule I end up with,
(x-4)d(2) + (2)d(x-4)
=(x - 4)(0) + (2)(1)
= 0 + 2
Similarly,
(x^2 + 2x + 1)d(2) + (2)d(x^2 + 2x + 1)
= (x^2 + 2x + 1)(0) + (2)(2x + 2)
= 0 + (4x + 4)
(d = derivative, i don't know how else to enter it in here.)
What I need clarification with is if we have a derivative of a constant multiplied by another function, does it always equal 0 because we multiply by 0? Or do we just remove the constant derivative?
So if we just remove the constant derivative the first equation would end up like
(x - 4) + (2x - 1) instead of 0 + (2x - 1).
Thank you in advance!