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Math Help - integrate the function....

  1. #1
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    integrate the function....

    i am supposed to integrate this function, but i have no idea, i completed the square hoping that would help but still no good, any thoughts? well here is an upload of the problem...sorry for the messy handwriting. thanks in advance.integrate the function....-image.jpg
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  2. #2
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    \frac{1}{x^2-12x+32} = \frac{1}{(x-4)(x-8)}<br />

    use partial fractions
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  3. #3
    MHF Contributor Calculus26's Avatar
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    There are 2 ways to approach this

    1) 1/[x^2 - 12x +32] =1/[ (x-8)(x-4)]

    and Use partial fraction decomp

    2) x^2 - 12x +32 = (x-6)^2 - 4

    use trig sub

    Let x -6 = 2sec(t)
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  4. #4
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    Thumbs up

    ok im gonna take a look at the partial fraction, only because i havent learned that method before..thanks again!
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