i am supposed to integrate this function, but i have no idea, i completed the square hoping that would help but still no good, any thoughts? well here is an upload of the problem...sorry for the messy handwriting. thanks in advance.
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$\displaystyle \frac{1}{x^2-12x+32} = \frac{1}{(x-4)(x-8)} $ use partial fractions
There are 2 ways to approach this 1) 1/[x^2 - 12x +32] =1/[ (x-8)(x-4)] and Use partial fraction decomp 2) x^2 - 12x +32 = (x-6)^2 - 4 use trig sub Let x -6 = 2sec(t)
ok im gonna take a look at the partial fraction, only because i havent learned that method before..thanks again!
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