(3y^2 + 2y)y' = xcosx

xyy'=ln(x) ; y(1)=2

for the first one i get y^3 + y^2= (x^2) sin(x) +cos(x) + C (constant)

and the second one is y^2 + ln(x)^2 +4

the problem is there is no way i can define those two as function y of x or function x of y

because of the exponents.

So my question is, if a question is asking for a solution to a differential equation, can we just leave it as that above?