How am I supposed to know that ln9 - ln1 = 2*ln3 ?
How am I supposed to know that ln9 - ln1 = 2*ln3 ? For example, I would know that 9/4 - 3/2 is 15/4 because I can convert 3/2 into 6/4 but how do I such a thing with logarithms?
Any input would be greatly appreciated!
Thanks in advance!
How am I supposed to know that ln9 - ln1 = 2*ln3 ? For example, I would know that 9/4 - 3/2 is 15/4 because I can convert 3/2 into 6/4 but how do I such a thing with logarithms?
Any input would be greatly appreciated!
Thanks in advance!
From the basics of logs you're expected to know that . This is because
This expression is simplified using the log power law: and the knowledge of the fact that
Thus
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Laws of logarithms. in all cases and in all cases
Last edited by e^(i*pi); Jan 30th 2010 at 09:07 AM.
Reason: adding latex/log laws