Find derivative of y=x^x^x.
Whoa. Not sure how to attack this but heres what i think:
use logarithmic diff, so it would be xln(x^x)
Then product rule, so x*derivative of ln(x^x)+ln(x^x), or can i do the same law of logs again to make it x*derivative of ln(xln(x))+ln(x)?
I figure it out. I tried applying ln again, but it got wayy to sloppy. Since i solved the derivative for x^x before separately while trying to do this problem i was able to just plug in the derivative when doing the product rule on ln(y)=x^xln(x). My final answer was x^x^x[((x^x)*1/x)+(ln(x)*x^x(ln(x)+1)]. I then found this video on youtube and the guy did exactly what i did . Thanks for all the help!
If you want to check out the video, its at YouTube - Calculus: Derivative of x^(x^x)