F (x) = $\displaystyle 5^{-2x^2+x}$

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- Jan 28th 2010, 04:27 PMwopashuiHelp with Differentiating
F (x) = $\displaystyle 5^{-2x^2+x}$

- Jan 28th 2010, 04:33 PMdrumist
The general rule for a constant raised to a function of x is:

if $\displaystyle f(x)=a^{g(x)}$ then

$\displaystyle f'(x) = g'(x) \cdot \ln(a) \cdot a^{g(x)}$

Can you apply the rule? - Jan 28th 2010, 04:34 PMGeneral
- Jan 30th 2010, 11:43 AMwopashui
- Jan 30th 2010, 01:19 PMDefunkt