eliminating parameter to find cartesian eq.

**easyliver** · Jan 28th 2010, 03:26 PM

new here...and about 12 yrs removed from Calculus, sorry if all my questions are rudimentary, alas I should have taken this when my brain was a bit more pliable...

x=t^6 and y=t^6 t (less than or equal to) 0

**pickslides** · Jan 28th 2010, 03:43 PM

Originally Posted by easyliver

x=t^6 and y=t^6 t (less than or equal to) 0

$x= t^6$ and $y = t^6$ for $t\leq 0 \implies y=x$

**HallsofIvy** · Jan 29th 2010, 02:08 AM

Originally Posted by pickslides

$x= t^6$ and $y = t^6$ for $t\leq 0 \implies y=x$

For $x\ge 0$ .

The graph is a half-line, not the entire line y= x.

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