Thread: eliminating parameter to find cartesian eq.

new here...and about 12 yrs removed from Calculus, sorry if all my questions are rudimentary, alas I should have taken this when my brain was a bit more pliable...

x=t^6 and y=t^6 t (less than or equal to) 0

Originally Posted by easyliver

x=t^6 and y=t^6 t (less than or equal to) 0

$\displaystyle x= t^6 $ and $\displaystyle y = t^6 $ for $\displaystyle t\leq 0 \implies y=x$

Originally Posted by pickslides

$\displaystyle x= t^6 $ and $\displaystyle y = t^6 $ for $\displaystyle t\leq 0 \implies y=x$

For $\displaystyle x\ge 0$.

The graph is a half-line, not the entire line y= x.