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Math Help - eliminating parameter to find cartesian eq.

  1. #1
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    Unhappy eliminating parameter to find cartesian eq.

    new here...and about 12 yrs removed from Calculus, sorry if all my questions are rudimentary, alas I should have taken this when my brain was a bit more pliable...

    x=t^6 and y=t^6 t (less than or equal to) 0
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  2. #2
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    Quote Originally Posted by easyliver View Post

    x=t^6 and y=t^6 t (less than or equal to) 0

    x= t^6 and y = t^6 for t\leq 0 \implies  y=x
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  3. #3
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    Quote Originally Posted by pickslides View Post
    x= t^6 and y = t^6 for t\leq 0 \implies  y=x
    For x\ge 0.

    The graph is a half-line, not the entire line y= x.
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