Hello! I am stuck on this problem. I have tried lots of things, but just can't seem to get the right answer. Thanks for your help!
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$\displaystyle \ln(3x)=\ln3+\ln x,$ can you proceed?
I tried substituting that in for ln(3x), but I'm still getting the wrong answer. Could you help me out with some more steps? Thanks!
Originally Posted by jsl I tried substituting that in for ln(3x), but I'm still getting the wrong answer. Could you help me out with some more steps? Thanks! Let $\displaystyle u=\ln3x$, then $\displaystyle du=\frac{3}{3x}dx=\frac{1}{x}dx$ Now Note that $\displaystyle \int\frac{\ln3x}{x}dx=\int(\ln3x)\left(\frac{1}{x} \right)dx$ So, we make the substution $\displaystyle \int(u)du$
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