f(x)= (e^x) / (4 - x^2) x <,= 0
sin(pi/2 - x) / (x+2)^2 x>0
i found that f(0)=LHL=RHL=1/4
thus, f(x) is continuous at x=0
however, there's another question that ask "locate, with justification, any points of discontinuity"
i figured that when x= -2, it became discontinuity,
however, what kind of discontinuity is it?
f(-2) = LHL = e^-2 / 0
RHL = 3/0
is this removable discontinuity?