f(x)= (e^x) / (4 - x^2) x <,= 0

sin(pi/2 - x) / (x+2)^2 x>0

i found that f(0)=LHL=RHL=1/4

thus, f(x) is continuous at x=0

however, there's another question that ask "locate, with justification, any points of discontinuity"

i figured that when x= -2, it became discontinuity,

however, what kind of discontinuity is it?

f(-2) = LHL = e^-2 / 0

RHL = 3/0

is this removable discontinuity?