f(x) = abs (x+3) x<0
2x + 1 x=0
(x+2)^2 - 1 x>0
i found
lim x->0 = 1
lim x->0 + - = 3
so f(x) is not continuous
but is this removable discontinuity? or jump discontinuity?
how do i figure it out which is the one?
f(x) = abs (x+3) x<0
2x + 1 x=0
(x+2)^2 - 1 x>0
i found
lim x->0 = 1
lim x->0 + - = 3
so f(x) is not continuous
but is this removable discontinuity? or jump discontinuity?
how do i figure it out which is the one?
If the left-hand and right-hand limits at a point are equal, then it is a removable discontinuity. The idea is that you could "remove" the discontinuity by filling in the hole, leaving you with a smooth curve.
If they aren't equal, it is a jump discontinuity.