If I have this problem:

lim as h -> 0

$\displaystyle

\frac{sin( \frac{\pi}{2} + h) - 1}{h}

$

And I have these answer choices:

A. $\displaystyle f'(\frac{\pi}{2}), f(x)=sinx$

B. $\displaystyle f'(\frac{\pi}{2}), f(x)=\frac{sinx}{x}$

C. $\displaystyle f'(1), f(x)=sinx$

D. $\displaystyle f'(1), f(x)=sin(x + \frac{\pi}{2})$

E. $\displaystyle f'(0), f(x)=sinx$

What does this really mean? like, I don't understand what f'(0) would imply, for instance.