Need some help with this one: lim x-> inf of (1-e^x) / (1+e^x) The answer should be -1 but I don't get how that is so. When you plug in infinity you get -inf/inf right? How does this problem work out algebraically?
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$\displaystyle \frac{1-e^{x}}{1+e^{x}}=\frac{e^{-x}-1}{e^{-x}+1},$ can you compute its limit now?
Originally Posted by Krizalid $\displaystyle \frac{1-e^{x}}{1+e^{x}}=\frac{e^{-x}-1}{e^{-x}+1},$ can you compute its limit now? Thank-you! I get it now!
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