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**qbkr21** Guys as always I appreciate you help. I think this is one of the best sites on the internet. I do however have a question:

A particle moves along a straight line and its position at time t s given by s(t)= 2t^3 - 15 t^2 + 24 t where s is measured in feet and t in seconds. Find the velocity (in ft/sec) of the particle at time t=0___?___. The particle stops moving twice, once when t=A and again when t=B where A<B. A is ___?____

& B is ___?___. What is the position of the particle at time 10 ___?____.

Thanks Again!