$\displaystyle \int\!x sec^2 x^2dx $ I have absolutely no idea, what this thing is
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Originally Posted by 450081592 $\displaystyle \int\!x sec^2 x^2dx $ I have absolutely no idea, what this thing is Substitute $\displaystyle u = x^2$, then use the fact that the integral of $\displaystyle \sec^2u$ is $\displaystyle \tan u$.
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