The distance is the integral of the speed or |v(t)|
1/t^2 -1/25 which is >0 for 3 < t < 5 and <0 5 < t < 6
you have integral(1/t^2 -1/25) 3 < t < 5 and
integral(1/25 -1/t^2) 5 < t < 6
A particle moves in a straight line with velocity ft/s. Find the total displacement and total distance traveled over the time interval .
I solved the displacement however I'm not sure how to find the total distance traveled. Thanks to anyone who can help!