the side of the cubes are increasing at the rate of 0.4cm per second. find:
1.the rate the volume increases
2.the rate the surface area is increasing when sides are 10cm
here's how i went about it.
v=s^3 where v is volume, s is length of the side
dv/dt = 3s^2 (ds/dt)
so from the question, the sides are increasing at a rate of 0.4cm per second.
from that you can get ds/dt i think. so how would i write that as ds/dt?
i'm guessing ds/dt = 1.04s as it increases by 4% persecond if the side was intially 1cm but i have no idea how to write ds/dt generally,
if i solve the first question then i'm pretty sure i can do part two.
thanks in advanced for any help