hmm any help?
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Originally Posted by usagi_killer hmm any help? one of, i am sure, many ways: multiply by you get Now expand the numerator and break this into 3 integrals. you should be able to handle each pretty easily
Originally Posted by usagi_killer hmm any help? Multiply the integrated function by With some algebra and trigonometric identities, you will get: For the first: use a well-known trigometric identity. For the second: use a U-Substitution. For the third: Its a well-known integral.
Originally Posted by usagi_killer hmm any help? . I'm sure you can go from there.
Originally Posted by General Multiply the integrated function by With some algebra and trigonometric identities, you will get: For the first: use a well-known trigometric identity. For the second: use a U-Substitution. For the third: Its a well-known integral. u-sub is not necessary for the second
Originally Posted by Jhevon u-sub is not necessary for the second But it solves it.
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