# differentiation f(x)=xe^(5x), f'(x)=(1/5)

• Mar 13th 2007, 06:42 PM
darkblue
differentiation f(x)=xe^(5x), f'(x)=(1/5)
differentiation f(x)=xe^(5x), f'(x)=(1/5)

ok so i got 5xe^5x + e^5x

now what do i do with the (1/5).
and is my differentiation correct?
• Mar 13th 2007, 06:47 PM
Jhevon
Quote:

Originally Posted by darkblue
differentiation f(x)=xe^(5x), f'(x)=(1/5)

ok so i got 5xe^5x + e^5x

now what do i do with the (1/5).
and is my differentiation correct?

your differentiation is correct. as to what to do with the (1/5), i think you just equate it to the derivative and i guess try to solve for x (which i think will be hard) what were the full instructions?
• Mar 13th 2007, 06:51 PM
Jhevon
Quote:

Originally Posted by Jhevon
your differentiation is correct. as to what to do with the (1/5), i think you just equate it to the derivative and i guess try to solve for x (which i think will be hard) what were the full instructions?

ok, so maybe its just me, but i tried equating and solving for x, cant do it, as i thought. so im guessing thats not what the question asked
• Mar 13th 2007, 06:59 PM
darkblue
thank you.
i'm confused also.
but i don't know if he means to do the integral of it.
that was all the directions.

like should i do integral of 5e^(5x)x+(e^5x) x dx ?
• Mar 13th 2007, 07:05 PM
Jhevon
Quote:

Originally Posted by darkblue
thank you.
i'm confused also.
but i don't know if he means to do the integral of it.
that was all the directions.

like should i do integral of 5e^(5x)x+(e^5x) x dx ?

you're telling me the question was phrased just like that?

"differentiation f(x)=xe^(5x), f'(x)=(1/5)"