It asked which direction the following was traced.
x=t
y= sqrt (3-t)
Interval: t <= 3.
But which direction, either right or left? .. is this even possible?
$\displaystyle dx/dt= 1$ which is positive. $\displaystyle \frac{dy}{dt}= \frac{3}{2\sqrt{3-t}}$ which is also positive. The curve will be traced in the direction up and to the right.