Thread: Find the discontinuities of a piecewise function

y=(3x+1) / (x+2), x < 3, x can't = 2
y= sqrt(x+1), X > (or equal) 3

I have an infinite discontinuity at x = -2 but my teacher said there's one more. What is it?

Also, where is this function differentiable

y = sqrt(8-5x) / (x+1)

is it x<= 5/8, x /=/ 1?

i didnot get your question well. could u define the function more accurately??

y= (3x+1) / (x+2), x < 3, x can't = -2
y= sqrt(x+1), X > (or equal) 3

y can equal both of these things. the Squareroot of (x+1) on the interval x >= 3 and (3x+1) divided by (x+2) on the interval x < 3, x can't = -2

are my answer correct?