y=(3x+1) / (x+2), x < 3, x can't = 2

y= sqrt(x+1), X > (or equal) 3

I have an infinite discontinuity at x = -2 but my teacher said there's one more. What is it?

Also, where is this function differentiable

y = sqrt(8-5x) / (x+1)

is it x<= 5/8, x /=/ 1?