Can anyone help me evaluate this limit?

$\displaystyle \lim_{x\to 0} \frac{x^2}{1-\cos2x} $

I can see that the numerator approaches 0 faster and that you can say that this is equal to $\displaystyle (x)(\frac{x}{1-\cos2x}) $ but i'm not sure where to go from there. Oh and the answer is 1/2 and i cant use L'hospital's theorem.

Thanks!