The largest these number can be, and still be rounded to 2.0 and 3.0, are 2.5 and 3.5. 2x+ y, in that case, would be 5.0+ 3.5= 8.5. The smallest they can be are 1.5 and 2.5. In that case, 2x+ y would be 5.5. 2(2.0)+ 3.0= 7. Since 8.5-7= 1.5 and 7- 5.5= 1.5, the "absolute error is 1.5. The "relative error" is 1.5/7= 3/14 or about .214.2.If x = 2.0, y = 3.0 and z = 4.0, all are corrected to 1 decimal places, calculate the absolute and relative error for
(i) 2x + y
Now, try this one yourself.(ii)
Since there are no conditions on which can be planted on the north side and which on south, we can really ignore that distinction. This is really about planting 9 trees in 9 places. If they were all different, there would be, of course, 9! diferent ways of doing that. But that includes cases in which two figs, say were switched while all other trees remainded in the same place and we don't want to count that as two different ways. Since there are 3 figs, there are 3! ways to interchange them while leaving the other trees the same- for every way of planting the trees, we have counted 3! that are really the same since they only involve swapping fig trees. That means that the number of ways of planting the trees if we don't count those as different is 9!/3!. Of course, we can treat the prunes and magnolias the same way- the number of distinct ways of planting these trees is 9!/(3!4!2!)3.The position of nine trees which are to be planted a long the sides of a road, five on the north side and four on the south side.
If there are 3 figs, 4 prunes and 2 magnolias, find the number of different ways in which these could be planted assuming that the trees of the same species are identical.