yes it should. :( Check out the hundred other posts here, I apologize.

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- Jan 23rd 2010, 09:42 PMVonNemo19
- Jan 23rd 2010, 09:44 PMProve It
- Jan 24th 2010, 03:04 AMArchie Meade
hi naomi,

following on from Prove It's good post,

in terms of the substitution you are working with,

we have

If we write this as

then

hence

- Jan 24th 2010, 07:26 AMnaomi
thank you all for your help.

- Jan 26th 2010, 12:46 PMnaomi
Hi Prove it,

your trigonometric approach is almost clear to me. There is one thing which I don't completely get.

How do you get from this step sqrt((1/4)^2-(1/4sin (theta))^2) to 1/4 sqrt(1-sin^2(theta))? - Jan 26th 2010, 07:29 PMProve It
- Jan 26th 2010, 11:27 PMnaomi
Hi Prove it

Could you explain how you get from

sqrt(-(1/4)^2((sin^2)(theta)))

to

sqrt((1-sin^2(theta))) - Jan 27th 2010, 08:34 PMProve It
Check my edit.

- Jan 28th 2010, 12:06 AMnaomi
Thank you.