I blanked on how to solve this. I thought i take the seventh root and put it inside, so it would be (x)^7/2 then differentiate ...but i was wrong. Any takers? Thanks!
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Wouldn't it just be (1/(seventh root of x)) * Chain rule?
$\displaystyle \sqrt[7]{x} = x^{1/7}$ You can use chain rule.
Or even easier: $\displaystyle f(x) = \ln(\sqrt[7]{x}) = \ln(x^{1/7}) = \frac{1}{7} \ln(x)$
It was that part i forgot. thanks.
f(x)=(1/7)lnx so f'(x)=1/7x
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